I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista
Ultimate 0x32 bit, for this I did the following things

- Set the registry value for this device at the registry key
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows
NT\CurrentVersion\EMDMgmt\"Corresponding device Name" as

-- CacheSizeInMB = 0x0000010e (270)
-- CacheStatus = 0x00000001 (1)
-- DeviceStatus = 0x00000002 (2)
-- DoRetestDevice = 0x00000000 (0)
-- HasSlowRegions = 0x00000000 (0)
-- LastTestedTime = 0x00000000 (0)
-- PhysicalDeviceSizeMB = 0x0000017f (383)
-- ReadSpeedKBs = 0x3b9aca00 ( 1000000000 )
-- RecommendedCacheSizeMB = 0x0000010e (270)
-- USBVersion = 0x00020000 (131072)
-- WriteSpeedKBs = 0x3b9aca00 ( 1000000000 )

- Restart the "ReadyBoost" service

The RAMDrive has not configured as ReadyBoost and the
"readyboost.sfcache" has not created on the RAMDrive; If I right click
on the RAMDrive and configure it as ReadyBoost from properties then it
works properly; the "readyboost.sfcache" file has been created on the
drive also and the registry value has been set as above.

One more thing, The same procedure I have followed for a USB Flash
drive and it can be configured as ReadyBoost by both way.

NB: To make a ReadyBoost on RAMDisk, the RAMDisk type must be USBDrive
Type.

Could anybody please tell me how can I solve the problem?

Thanks in advance,
Imran


--
ImranHossain

In message
ImranHossain was claimed to have wrote:


I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista
Ultimate 0x32 bit, for this I did the following things

- Set the registry value for this device at the registry key
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows
NT\CurrentVersion\EMDMgmt\"Corresponding device Name" as

-- CacheSizeInMB = 0x0000010e (270)
-- CacheStatus = 0x00000001 (1)
-- DeviceStatus = 0x00000002 (2)
-- DoRetestDevice = 0x00000000 (0)
-- HasSlowRegions = 0x00000000 (0)
-- LastTestedTime = 0x00000000 (0)
-- PhysicalDeviceSizeMB = 0x0000017f (383)
-- ReadSpeedKBs = 0x3b9aca00 ( 1000000000 )
-- RecommendedCacheSizeMB = 0x0000010e (270)
-- USBVersion = 0x00020000 (131072)
-- WriteSpeedKBs = 0x3b9aca00 ( 1000000000 )

- Restart the "ReadyBoost" service

The RAMDrive has not configured as ReadyBoost and the
"readyboost.sfcache" has not created on the RAMDrive; If I right click
on the RAMDrive and configure it as ReadyBoost from properties then it
works properly; the "readyboost.sfcache" file has been created on the
drive also and the registry value has been set as above.

One more thing, The same procedure I have followed for a USB Flash
drive and it can be configured as ReadyBoost by both way.

NB: To make a ReadyBoost on RAMDisk, the RAMDisk type must be USBDrive
Type.

Could anybody please tell me how can I solve the problem?

The short answer is: don't. SuperFetch will do the same job, with far
less overhead then ReadyBoost.

On Fri, 16 Jan 2009 00:17:22 -0600, ImranHossain
wrote:

I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista
Ultimate 0x32 bit, for this I did the following things

WHY?

Readyboost is for systems that are low on RAM (2gig or less). If you
have more than 2 Gigs of RAM, Readyboost will not help you at all.

If you have less, you will merely be reducing your effective RAM.

Hi Rob Talley,

So you wanna tell that ReadyBoost will not improve any performance if
the RAM size is greater than 2 GB, right?

However, I have created a RAMDisk (383 MB) on a system that has 2 GB
RAM and wanna make ReadyBoost as the above method then what should I do?

Dave Warren,

Could you please explain more. I need to write a program that can
create ReadyBoost on RAMDrive, and in analysis phase I got the mentioned
problem. so is three any solution?

Thanks
Imran Hossain


--
ImranHossain

In message
ImranHossain was claimed to have wrote:

So you wanna tell that ReadyBoost will not improve any performance if
the RAM size is greater than 2 GB, right?

That isn't strictly true, but it's a good rule of thumb.

However, I have created a RAMDisk (383 MB) on a system that has 2 GB
RAM and wanna make ReadyBoost as the above method then what should I do?

For what purpose? Why are you trying to accomplish this?

Do you realize that at best you'll cause a minor performance hit, and at
worst you'll cause a significant performance hit?

On Fri, 16 Jan 2009 02:04:55 -0600, Rob Talley
wrote:

On Fri, 16 Jan 2009 00:17:22 -0600, ImranHossain
wrote:

I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista
Ultimate 0x32 bit, for this I did the following things

WHY?

Readyboost is for systems that are low on RAM (2gig or less). If you
have more than 2 Gigs of RAM, Readyboost will not help you at all.


My advice is not to use readyboost no matter how much RAM you have.

If you have 2GB or more of RAM, the little it might do for you is so
slight as to be almost unnoticeable.

And if you have less than 2GB of RAM, you would do much better to
spend your money on upgrading your RAM to 2GB than on buying a device
for ReadyBoost use.

So, in general, I always recommend against using ReadyBoost.

--
Ken Blake, Microsoft MVP - Windows Desktop Experience
Please Reply to the Newsgroup

I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista

This is completely the wrong thing to do. There is no case for using up RAM
as a RAM-disk, unless you have a badly-written application that insists on
doing its own memory management rather than relying on the OS to do the job.

And then to compound that by configuring this RAM-disk as Readyboost is even
more inappropriate.

If Windows would benefit from using RAM in this convoluted way, it would be
built into the OS. They've been fine-tuning the memory management in the
kernel for fifteen years, and its an immensely complicated topic.

No, forget about it. To get the best performance is very simple - throw as
much RAM as you can at Vista and leave Vista to decide how to use it. Set
your paging size to a generous, and fixed, size on your fastest disk. And
forget about Readyboost (it was only a kludge to help speed up the most
marginal of hardware).

That's it. Don't fiddle with anything else.

SteveT

"Steve Thackery" wrote:

I want to create a ReadyBoost on a RAMDisk (manually) in Windows Vista

This is completely the wrong thing to do. There is no case for using up RAM
as a RAM-disk, unless you have a badly-written application that insists on
doing its own memory management rather than relying on the OS to do the job.

And then to compound that by configuring this RAM-disk as Readyboost is even
more inappropriate.

If Windows would benefit from using RAM in this convoluted way, it would be
built into the OS. They've been fine-tuning the memory management in the
kernel for fifteen years, and its an immensely complicated topic.

No, forget about it. To get the best performance is very simple - throw as
much RAM as you can at Vista and leave Vista to decide how to use it. Set
your paging size to a generous, and fixed, size on your fastest disk. And
forget about Readyboost (it was only a kludge to help speed up the most
marginal of hardware).

That's it. Don't fiddle with anything else.

SteveT

What do you do? Wait until a half-dozen or so replies come in then
summarize what they said and post it as your own?

What do you do? Wait until a half-dozen or so replies come in then
summarize what they said and post it as your own?

Nope, I express my own views. I try to tell a complete story, especially if
I feel the existing replies are too brief, unhelpful, don't address the
original question, or make assertions without explanations.

Like all of yours.

Now go away, you tedious little person, before I squirt you with fly spray.

SteveT

"ReadyBoost" is a title given to a function/utility by which Vista uses a
sold state device (RAM disk does not meet the criteria ) - Vista compares
the read/write specs of the device against a set of default values and
those of the HD. If spec are not equivalent or better Vista will not use
the device.

Non-sequential read/writes are send to the ReadyBoost device and sequential
to the HD - increase in performance depends on type of HD activity. In
addition, ReadyBoost assists Vista in tracking computer usage over a period
of time and provides data to speed up startup and retrieval times (Defrag
utilizes the data). Since ReadyBoost use is contingent on read/write specs,
it is of more value on laptops.

ReadyDrive performs the same function when a hybrid HD is installed.